Miner's Loading Number

The Miner's Loading Number is very big, so big it is exactly $$\cos\frac{\operatorname{TREE}\left(3\right)\pi}{2}\%$$ of the diameter of the Box (Leftunknown said he didn't want the Omniverse appearing 😢). It uses the Loader Function (Dy(x)).

The formula:

$$\operatorname{Ml}_1 = \underbrace{D^{D^{D^{\cdots^{D^{1}(1)}(1)}(1)}(1)}(1)}_{\text{what is D(1)}}$$

$$\operatorname{Ml}_2 = \underbrace{D^{D^{D^{\cdots^{D^{2}(2)}(2)}(2)}(2)}(2)}_{\text{what is D(2)}}$$

$$\operatorname{Ml}_3 = \underbrace{D^{D^{D^{\cdots^{D^{3}(3)}(3)}(3)}(3)}(3)}_{\text{what is D(3)}}$$

$$\vdots$$

$$\operatorname{Ml}_{132} = \underbrace{D^{D^{D^{\cdots^{D^{132}(132)}(132)}(132)}(132)}(132)}_{\text{D(132)}}$$

$$\operatorname{Ml}_x = \underbrace{D^{D^{D^{\cdots^{D^{x}(x)}(x)}(x)}(x)}(x)}_{D(x) \text{times}}$$

Now, let's nest it!

$$\operatorname{Ml}_x^1 = \underbrace{Ml_x}_{Ml_x}$$

$$\operatorname{Ml}_x^2 = \underbrace{Ml_{Ml_x}}_{Ml_x}$$

$$\operatorname{Ml}_x^3 = \underbrace{Ml_{Ml_{Ml_x}}}_{Ml_x}$$

$$\vdots$$

The final number is *drumroll sounds* $$\operatorname{Ml}_{2147483648}^{2147483648}$$.

I don't know if it's bigger than Rayo's number (I think it's smaller), but I am g999% sure it is a whole lot bigger than Loader's number.